In mildly alkaline medium,thiosulphate ion is | vedclass

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(C) In mildly alkaline medium,the reaction between thiosulphate ion $(S_2O_3^{2-})$ and permanganate ion $(MnO_4^-)$ is as follows:$8MnO_4^- + 3S_2O_3

Vedclass · Accepted Answer

$6$

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(C) In mildly alkaline medium,the reaction between thiosulphate ion $(S_2O_3^{2-})$ and permanganate ion $(MnO_4^-)$ is as follows:$8MnO_4^- + 3S_2O_3^{2-} + H_2O \rightarrow 8MnO_2 + 6SO_4^{2-} + 2OH^-$Here,the product $A$ is the sulphate ion $(SO_4^{2-})$.To find the oxidation state of sulphur $(S)$ in $SO_4^{2-}$:Let the oxidation state of $S$ be $x$.$x + 4(-2) = -2$$x - 8 = -2$$x = +6$Therefore,the oxidation state of sulphur in $A$ is $6$.

In mildly alkaline medium,thiosulphate ion is oxidized by $MnO_4^-$ to $A$. The oxidation state of sulphur in $A$ is ..... .

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